Calculate percentile JEE Main Score | PERCENTILE AND NORMALIZATION OF MARKS JEE Main www.jeemain.nic.in - CETJob

# Calculate percentile JEE Main Score | PERCENTILE AND NORMALIZATION OF MARKS JEE Main www.jeemain.nic.in

## Calculate percentile JEE Main Score | PERCENTILE AND NORMALIZATION OF MARKS JEE Main

ABOUT PERCENTILE AND NORMALIZATION OF MARKS OF CLASS 12TH/QUALIFYING
EXAMINATION
1. The percentage of marks and percentile are totally different entities hence the candidates should not confuse with both the above terms.
2. Percentage is a number out of 100.

3. Percentile Score of a candidate in a Board or JEE Main 2018 will reflect how many Candidates have scored below that candidate in his/her Board or JEEMain 2018) Examination.
A Percentile score is the value below which a certain percent of observations fall. For example, the 40th Percentile is the value or score below which 40 Percent of the observations may be found.
The Percentile of a Candidate will be calculated as 100 X Number of candidates in the ‘group’ with aggregate marks less than the candidate Total number of the candidates in the ’group’
Example: Suppose in a particular Board:

No of Candidates Registered =13918 and No of Candidates Appeared = 13711
a. A Candidate who has scored 50% marks in the Board and 2218 candidates have scored below him; his Percentile score will be calculated as follows
Percentile score for 50% marks in the Board =        2218 * 100 / 13711 = 16.18
b. A Candidate who has scored 60% marks in the Board and 6865 candidates have scored below
him; his Percentile score will be calculated as follows
Percentile score for 60% marks in the Board =  6865 * 100 / 13711 = 50.07
c. A Candidate who has scored 90% marks in the Board and 13615 candidates have scored below
him; his Percentile score will be calculated as follows
Percentile score for 90% marks in the Board = 13615 * 100 / 13711 = 99.30
With these examples, it is clear that percentage of marks obtained by a candidate (50%, 60% or
90%) is different from the percentile score (16.18, 50.07 or 99.30).
4. The normalized Qualifying examination marks will be based on the position of the candidate in the
Board (i.e. his/her percentile score). The percentile score a candidate gets in his/her board will
mainly contribute to his/her normalized marks.
5. The candidates, willing to appear in the improvement examination to improve the qualifying
examination marks, will have to appear in all the five subjects for improvement.
6. In the percentile system, the total marks (of all five subjects) obtained/shown on the mark-sheet of a
particular year are required in JEEMain 2018 and also in JEE (Advanced). The marks from two different years (i.e. marks for 3 subjects from year 2015 and marks for other 2 subjects from 2016) mark-sheets cannot be considered for percentile calculation.

## Normalization Procedure Adopted in JEE(Main) for Admission to NITs/IIITs/CFTIs on the Basis of Class 12th Qualifying examination marks

The detailed procedure for normalization of Qualifying examination marks is as follows:-
i. Note down the aggregate marks (A0) obtained by each student in JEE- Main.
ii. Compute the percentile (P) of each student on the basis of aggregate marks in his/her own board
(B0) computed from the list of five subjects specified (each marked out of 100). The percentile is to
be computed among all students of the board whose subject combinations meet the eligibility
criteria of JEE-Main. The variable B0 is only a base for calculating percentile (P), which is further used
to get corresponding JEE (Main) marks.
iii. Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India level.
Regard this as B1.
iv. Also, determine the JEE- Main aggregate marks corresponding to percentile (P) among the set of
aggregate scores obtained in the JEE-Main by the students of that board. Regard this as B2.
The normalized board score of the candidate was computed as:
Bfinal = 0.5 * (B1 + B2)
For the purpose of admission to CFTIs where it has been decided to use the JEE Mains performance
and the Normalized Board performance in the 60:40 ratio, the composite score for drawing the merit
list was computed as:
C = 0.6 * AO + 0.4 * Bfinal
Five subjects to be used for normalization:-
1. Physics
2. Mathematics
3. Any one of the subjects Chemistry, Biology, Biotechnology and Technical Vocational subject
4. One language
5. Any subject other than the above four subjects.
In respect of 3, 4 and 5, the best mark in a given category will be chosen.